वर्गमूल सर्पिल में \(\sqrt{1368}\) का अंतराल पहचानते समय कौन-सा निष्कर्ष सही है?

While identifying the interval of \(\sqrt{1368}\) in a square root spiral, which conclusion is correct?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(36<\sqrt{1368}<37\)

Step 1

Concept

Because \(36^2=1296\) and \(37^2=1369\). The number (1368) is less than (1369).

Step 2

Why this answer is correct

The correct answer is B. \(36<\sqrt{1368}<37\). Because \(36^2=1296\) and \(37^2=1369\). The number (1368) is less than (1369).

Step 3

Exam Tip

क्योंकि \(36^2=1296\) और \(37^2=1369\) हैं। (1368) (1369) से कम है।

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वर्गमूल सर्पिल में \(\sqrt{1368}\) का अंतराल पहचानते समय कौन-सा निष्कर्ष सही है? / While identifying the interval of \(\sqrt{1368}\) in a square root spiral, which conclusion is correct?

Correct Answer: B. \(36<\sqrt{1368}<37\). Explanation: क्योंकि \(36^2=1296\) और \(37^2=1369\) हैं। (1368) (1369) से कम है। / Because \(36^2=1296\) and \(37^2=1369\). The number (1368) is less than (1369).

Which concept should I revise for this Mathematics MCQ?

Because \(36^2=1296\) and \(37^2=1369\). The number (1368) is less than (1369).

What exam hint can help solve this Mathematics question?

क्योंकि \(36^2=1296\) और \(37^2=1369\) हैं। (1368) (1369) से कम है।