वर्गमूल सर्पिल में \(\sqrt{48}\) के बाद बनने वाले कर्ण और \(\sqrt{50}\) की तुलना में कौन-सा कथन सही है?

Which statement is correct when comparing the hypotenuse formed after \(\sqrt{48}\) and \(\sqrt{50}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

A. अगला कर्ण \(\sqrt{49}=7\) है और \(\sqrt{50}\) (7) और (8) के बीच हैThe next hypotenuse is \(\sqrt{49}=7\), and \(\sqrt{50}\) lies between (7) and (8)

Step 1

Concept

After \(\sqrt{48}\), \(\sqrt{49}=7\) is formed. Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8).

Step 2

Why this answer is correct

The correct answer is A. अगला कर्ण \(\sqrt{49}=7\) है और \(\sqrt{50}\) (7) और (8) के बीच है / The next hypotenuse is \(\sqrt{49}=7\), and \(\sqrt{50}\) lies between (7) and (8). After \(\sqrt{48}\), \(\sqrt{49}=7\) is formed. Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8).

Step 3

Exam Tip

\(\sqrt{48}\) के बाद \(\sqrt{49}=7\) बनता है। \(7^2<50<8^2\), इसलिए \(\sqrt{50}\) (7) और (8) के बीच है।

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वर्गमूल सर्पिल में \(\sqrt{48}\) के बाद बनने वाले कर्ण और \(\sqrt{50}\) की तुलना में कौन-सा कथन सही है? / Which statement is correct when comparing the hypotenuse formed after \(\sqrt{48}\) and \(\sqrt{50}\) in a square root spiral?

Correct Answer: A. अगला कर्ण \(\sqrt{49}=7\) है और \(\sqrt{50}\) (7) और (8) के बीच है / The next hypotenuse is \(\sqrt{49}=7\), and \(\sqrt{50}\) lies between (7) and (8). Explanation: \(\sqrt{48}\) के बाद \(\sqrt{49}=7\) बनता है। \(7^2<50<8^2\), इसलिए \(\sqrt{50}\) (7) और (8) के बीच है। / After \(\sqrt{48}\), \(\sqrt{49}=7\) is formed. Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8).

Which concept should I revise for this Mathematics MCQ?

After \(\sqrt{48}\), \(\sqrt{49}=7\) is formed. Since \(7^2<50<8^2\), \(\sqrt{50}\) lies between (7) and (8).

What exam hint can help solve this Mathematics question?

\(\sqrt{48}\) के बाद \(\sqrt{49}=7\) बनता है। \(7^2<50<8^2\), इसलिए \(\sqrt{50}\) (7) और (8) के बीच है।