Which option has zero \(-\frac{7}{2}\) for a linear polynomial?
Answer and explanation
Correct answer: \(2x+7\)
A zero of a polynomial is a value of x that makes the polynomial equal to 0. Substituting \(x=-\frac{7}{2}\) in \(2x+7\) gives \(2\left(-\frac{7}{2}\right)+7=-7+7=0\). Hence, \(2x+7\) is the correct option. The close distractor \(2x-7\) has zero \(\frac{7}{2}\), not \(-\frac{7}{2}\). Exam tip: the zero of \(ax+b\) is \(-\frac{b}{a}\).
Frequently asked questions
What is the correct answer to this question?
\(2x+7\)
Why is this the correct answer?
A zero of a polynomial is a value of x that makes the polynomial equal to 0. Substituting \(x=-\frac{7}{2}\) in \(2x+7\) gives \(2\left(-\frac{7}{2}\right)+7=-7+7=0\). Hence, \(2x+7\) is the correct option. The close distractor \(2x-7\) has zero \(\frac{7}{2}\), not \(-\frac{7}{2}\). Exam tip: the zero of \(ax+b\) is \(-\frac{b}{a}\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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