कौन-सी संख्या असांत अनावर्ती दशमलव होगी?

Which number will have a non-terminating non-recurring decimal?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \( \sqrt{6} \)

Step 1

Concept

\( \sqrt{6} \) is irrational, so its decimal is non-terminating non-recurring. An irrational decimal neither terminates nor repeats.

Step 2

Why this answer is correct

The correct answer is C. \( \sqrt{6} \). \( \sqrt{6} \) is irrational, so its decimal is non-terminating non-recurring. An irrational decimal neither terminates nor repeats.

Step 3

Exam Tip

\( \sqrt{6} \) अपरिमेय है, इसलिए इसका दशमलव असांत अनावर्ती होगा। अपरिमेय संख्या का दशमलव न समाप्त होता है न दोहरता है।

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Mathematics Answer, Explanation and Revision Hints

कौन-सी संख्या असांत अनावर्ती दशमलव होगी? / Which number will have a non-terminating non-recurring decimal?

Correct Answer: C. \( \sqrt{6} \). Explanation: \( \sqrt{6} \) अपरिमेय है, इसलिए इसका दशमलव असांत अनावर्ती होगा। अपरिमेय संख्या का दशमलव न समाप्त होता है न दोहरता है। / \( \sqrt{6} \) is irrational, so its decimal is non-terminating non-recurring. An irrational decimal neither terminates nor repeats.

Which concept should I revise for this Mathematics MCQ?

\( \sqrt{6} \) is irrational, so its decimal is non-terminating non-recurring. An irrational decimal neither terminates nor repeats.

What exam hint can help solve this Mathematics question?

\( \sqrt{6} \) अपरिमेय है, इसलिए इसका दशमलव असांत अनावर्ती होगा। अपरिमेय संख्या का दशमलव न समाप्त होता है न दोहरता है।