कौन-सी संख्या असांत अनावर्ती दशमलव होगी?
Which number will have a non-terminating non-recurring decimal?
Explanation opens after your attempt
C. \( \sqrt{6} \)
Concept
\( \sqrt{6} \) is irrational, so its decimal is non-terminating non-recurring. An irrational decimal neither terminates nor repeats.
Why this answer is correct
The correct answer is C. \( \sqrt{6} \). \( \sqrt{6} \) is irrational, so its decimal is non-terminating non-recurring. An irrational decimal neither terminates nor repeats.
Exam Tip
\( \sqrt{6} \) अपरिमेय है, इसलिए इसका दशमलव असांत अनावर्ती होगा। अपरिमेय संख्या का दशमलव न समाप्त होता है न दोहरता है।
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