कौन-सी संख्या \( \pi \) की तरह अपरिमेय है?

Which number is irrational like \( \pi \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \( \sqrt{26} \)

Step 1

Concept

\( \sqrt{26} \) is the square root of a non-perfect square, so it is irrational. \( \frac{22}{7} \) is rational, but \( \pi \) is not.

Step 2

Why this answer is correct

The correct answer is C. \( \sqrt{26} \). \( \sqrt{26} \) is the square root of a non-perfect square, so it is irrational. \( \frac{22}{7} \) is rational, but \( \pi \) is not.

Step 3

Exam Tip

\( \sqrt{26} \) अपूर्ण वर्ग का वर्गमूल है, इसलिए अपरिमेय है। \( \frac{22}{7} \) परिमेय है, \( \pi \) नहीं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

कौन-सी संख्या \( \pi \) की तरह अपरिमेय है? / Which number is irrational like \( \pi \)?

Correct Answer: C. \( \sqrt{26} \). Explanation: \( \sqrt{26} \) अपूर्ण वर्ग का वर्गमूल है, इसलिए अपरिमेय है। \( \frac{22}{7} \) परिमेय है, \( \pi \) नहीं। / \( \sqrt{26} \) is the square root of a non-perfect square, so it is irrational. \( \frac{22}{7} \) is rational, but \( \pi \) is not.

Which concept should I revise for this Mathematics MCQ?

\( \sqrt{26} \) is the square root of a non-perfect square, so it is irrational. \( \frac{22}{7} \) is rational, but \( \pi \) is not.

What exam hint can help solve this Mathematics question?

\( \sqrt{26} \) अपूर्ण वर्ग का वर्गमूल है, इसलिए अपरिमेय है। \( \frac{22}{7} \) परिमेय है, \( \pi \) नहीं।