\(4x^2+4xy+y^2-16\) का गुणनखंड रूप कौन सा है?
Which is the factorised form of \(4x^2+4xy+y^2-16\)?
Explanation opens after your attempt
A. ((2x+y-4)(2x+y+4))
Concept
First (4x-2+4xy+y-2=(2x+y)2), and \(16=4^2\). Exam tip: apply difference of squares at the end.
Why this answer is correct
The correct answer is A. ((2x+y-4)(2x+y+4)). First (4x-2+4xy+y-2=(2x+y)2), and \(16=4^2\). Exam tip: apply difference of squares at the end.
Exam Tip
पहले (4x-2+4xy+y-2=(2x+y)2) और \(16=4^2\) है। परीक्षा में वर्गों का अंतर अंत में लगाएं।
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