\(3x^2-17x+10\) का सही गुणनखंड कौन सा है?

Which is the correct factorisation of \(3x^2-17x+10\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. ( (3x-2)(x-5) )

Step 1

Concept

Expanding gives ( (3x-2)(x-5)=3x-2-17x+10 ). Exam tip: choose the pair with product (30) and sum (-17).

Step 2

Why this answer is correct

The correct answer is B. ( (3x-2)(x-5) ). Expanding gives ( (3x-2)(x-5)=3x-2-17x+10 ). Exam tip: choose the pair with product (30) and sum (-17).

Step 3

Exam Tip

फैलाने पर ( (3x-2)(x-5)=3x-2-17x+10 ) मिलता है। परीक्षा में (ac=30) और योग (-17) वाली जोड़ी लें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(3x^2-17x+10\) का सही गुणनखंड कौन सा है? / Which is the correct factorisation of \(3x^2-17x+10\)?

Correct Answer: B. ( (3x-2)(x-5) ). Explanation: फैलाने पर ( (3x-2)(x-5)=3x-2-17x+10 ) मिलता है। परीक्षा में (ac=30) और योग (-17) वाली जोड़ी लें। / Expanding gives ( (3x-2)(x-5)=3x-2-17x+10 ). Exam tip: choose the pair with product (30) and sum (-17).

Which concept should I revise for this Mathematics MCQ?

Expanding gives ( (3x-2)(x-5)=3x-2-17x+10 ). Exam tip: choose the pair with product (30) and sum (-17).

What exam hint can help solve this Mathematics question?

फैलाने पर ( (3x-2)(x-5)=3x-2-17x+10 ) मिलता है। परीक्षा में (ac=30) और योग (-17) वाली जोड़ी लें।