वर्गमूल सर्पिल में \(\sqrt{24}\) से \(\sqrt{25}\) बनने पर कौन-सा संयुक्त निष्कर्ष सही है?
When \(\sqrt{25}\) is formed from \(\sqrt{24}\) in a square root spiral, which combined conclusion is correct?
Explanation opens after your attempt
A. नया कर्ण (5) है और \(\sqrt{24}\) (4) और (5) के बीच हैThe new hypotenuse is (5), and \(\sqrt{24}\) lies between (4) and (5)
Concept
After \(\sqrt{24}\), \(\sqrt{25}=5\) is formed. Also \(4^2<24<5^2\), so \(\sqrt{24}\) lies between (4) and (5).
Why this answer is correct
The correct answer is A. नया कर्ण (5) है और \(\sqrt{24}\) (4) और (5) के बीच है / The new hypotenuse is (5), and \(\sqrt{24}\) lies between (4) and (5). After \(\sqrt{24}\), \(\sqrt{25}=5\) is formed. Also \(4^2<24<5^2\), so \(\sqrt{24}\) lies between (4) and (5).
Exam Tip
\(\sqrt{24}\) के बाद \(\sqrt{25}=5\) बनता है। साथ ही \(4^2<24<5^2\), इसलिए \(\sqrt{24}\) (4) और (5) के बीच है।
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