\(x^2-81\) का गुणनखंडन क्या होगा?

What will be the factorisation of \(x^2-81\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((x-9)(x+9))

Step 1

Concept

\(81=9^2\) and \(x^2-81\) is a difference of squares. So ((x-9)(x+9)) is obtained.

Step 2

Why this answer is correct

The correct answer is A. ((x-9)(x+9)). \(81=9^2\) and \(x^2-81\) is a difference of squares. So ((x-9)(x+9)) is obtained.

Step 3

Exam Tip

\(81=9^2\) है और \(x^2-81\) वर्गों का अंतर है। इसलिए ((x-9)(x+9)) मिलेगा।

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Mathematics Answer, Explanation and Revision Hints

\(x^2-81\) का गुणनखंडन क्या होगा? / What will be the factorisation of \(x^2-81\)?

Correct Answer: A. ((x-9)(x+9)). Explanation: \(81=9^2\) है और \(x^2-81\) वर्गों का अंतर है। इसलिए ((x-9)(x+9)) मिलेगा। / \(81=9^2\) and \(x^2-81\) is a difference of squares. So ((x-9)(x+9)) is obtained.

Which concept should I revise for this Mathematics MCQ?

\(81=9^2\) and \(x^2-81\) is a difference of squares. So ((x-9)(x+9)) is obtained.

What exam hint can help solve this Mathematics question?

\(81=9^2\) है और \(x^2-81\) वर्गों का अंतर है। इसलिए ((x-9)(x+9)) मिलेगा।