\(\sqrt{\frac{2}{9}}\) किस प्रकार की संख्या है?

What type of number is \(\sqrt{\frac{2}{9}}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. अपरिमेयIrrational

Step 1

Concept

\(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) which is irrational. Be careful when the numerator is not a perfect square.

Step 2

Why this answer is correct

The correct answer is B. अपरिमेय / Irrational. \(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) which is irrational. Be careful when the numerator is not a perfect square.

Step 3

Exam Tip

\(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) है जो अपरिमेय है। यदि अंश पूर्ण वर्ग न हो तो ध्यान रखें।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{\frac{2}{9}}\) किस प्रकार की संख्या है? / What type of number is \(\sqrt{\frac{2}{9}}\)?

Correct Answer: B. अपरिमेय / Irrational. Explanation: \(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) है जो अपरिमेय है। यदि अंश पूर्ण वर्ग न हो तो ध्यान रखें। / \(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) which is irrational. Be careful when the numerator is not a perfect square.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) which is irrational. Be careful when the numerator is not a perfect square.

What exam hint can help solve this Mathematics question?

\(\sqrt{\frac{2}{9}}=\frac{\sqrt{2}}{3}\) है जो अपरिमेय है। यदि अंश पूर्ण वर्ग न हो तो ध्यान रखें।