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What is the zero of the linear polynomial (6x+12)?रेखीय बहुपद (6x+12) का शून्यक क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(-2\)\(-2\)
To find the zero, set the polynomial equal to 0: \(6x+12=0\). Thus, \(6x=-12\), so \(x=-2\). On checking, \(6(-2)+12=0\); therefore, \(-2\) is the correct zero. \(-12\) is the constant term, not the zero. Exam tip: substitute the obtained value into the polynomial to verify your answer.शून्यक ज्ञात करने के लिए बहुपद को 0 के बराबर रखते हैं: \(6x+12=0\)। अतः \(6x=-12\), इसलिए \(x=-2\)। जाँच करने पर \(6(-2)+12=0\), इसलिए \(-2\) सही शून्यक है। \(-12\) केवल स्थिर पद है, शून्यक नहीं। परीक्षा टिप: मिले हुए मान को बहुपद में रखकर उत्तर की जाँच करें।
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