(\(\sqrt{125}+\sqrt{320}\)2) का मान क्या है?
What is the value of (\(\sqrt{125}+\sqrt{320}\)2)?
Explanation opens after your attempt
A. (845)
Concept
\(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{320}=8\sqrt{5}\), so the sum is \(13\sqrt{5}\). Its square is (845).
Why this answer is correct
The correct answer is A. (845). \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{320}=8\sqrt{5}\), so the sum is \(13\sqrt{5}\). Its square is (845).
Exam Tip
\(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{320}=8\sqrt{5}\), इसलिए योग \(13\sqrt{5}\) है। इसका वर्ग (845) है।
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