(\(\sqrt{125}+\sqrt{320}\)2) का मान क्या है?

What is the value of (\(\sqrt{125}+\sqrt{320}\)2)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (845)

Step 1

Concept

\(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{320}=8\sqrt{5}\), so the sum is \(13\sqrt{5}\). Its square is (845).

Step 2

Why this answer is correct

The correct answer is A. (845). \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{320}=8\sqrt{5}\), so the sum is \(13\sqrt{5}\). Its square is (845).

Step 3

Exam Tip

\(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{320}=8\sqrt{5}\), इसलिए योग \(13\sqrt{5}\) है। इसका वर्ग (845) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

(\(\sqrt{125}+\sqrt{320}\)2) का मान क्या है? / What is the value of (\(\sqrt{125}+\sqrt{320}\)2)?

Correct Answer: A. (845). Explanation: \(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{320}=8\sqrt{5}\), इसलिए योग \(13\sqrt{5}\) है। इसका वर्ग (845) है। / \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{320}=8\sqrt{5}\), so the sum is \(13\sqrt{5}\). Its square is (845).

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{320}=8\sqrt{5}\), so the sum is \(13\sqrt{5}\). Its square is (845).

What exam hint can help solve this Mathematics question?

\(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{320}=8\sqrt{5}\), इसलिए योग \(13\sqrt{5}\) है। इसका वर्ग (845) है।