\(x^2+6x+9-y^2\) का गुणनखंड रूप क्या है?
What is the factorised form of \(x^2+6x+9-y^2\)?
Explanation opens after your attempt
A. ((x+3-y)(x+3+y))
Concept
Here (x-2+6x+9=(x+3)2), then difference of squares applies. Exam tip: first convert the trinomial into a perfect square.
Why this answer is correct
The correct answer is A. ((x+3-y)(x+3+y)). Here (x-2+6x+9=(x+3)2), then difference of squares applies. Exam tip: first convert the trinomial into a perfect square.
Exam Tip
(x-2+6x+9=(x+3)2) है और फिर वर्गों का अंतर लगता है। परीक्षा में पहले त्रिपद को पूर्ण वर्ग बनाएं।
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