\(x^2+2xy+y^2-z^2-2z-1\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+2xy+y^2-z^2-2z-1\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((x+y-z-1)(x+y+z+1))

Step 1

Concept

First it becomes ((x+y)2-(z+1)2). In exams, understand \(-z^2-2z-1\) as (-(z+1)2).

Step 2

Why this answer is correct

The correct answer is A. ((x+y-z-1)(x+y+z+1)). First it becomes ((x+y)2-(z+1)2). In exams, understand \(-z^2-2z-1\) as (-(z+1)2).

Step 3

Exam Tip

पहले ((x+y)2-(z+1)2) बनता है। परीक्षा में \(-z^2-2z-1\) को (-(z+1)2) समझें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(x^2+2xy+y^2-z^2-2z-1\) का गुणनखंड रूप क्या है? / What is the factorised form of \(x^2+2xy+y^2-z^2-2z-1\)?

Correct Answer: A. ((x+y-z-1)(x+y+z+1)). Explanation: पहले ((x+y)2-(z+1)2) बनता है। परीक्षा में \(-z^2-2z-1\) को (-(z+1)2) समझें। / First it becomes ((x+y)2-(z+1)2). In exams, understand \(-z^2-2z-1\) as (-(z+1)2).

Which concept should I revise for this Mathematics MCQ?

First it becomes ((x+y)2-(z+1)2). In exams, understand \(-z^2-2z-1\) as (-(z+1)2).

What exam hint can help solve this Mathematics question?

पहले ((x+y)2-(z+1)2) बनता है। परीक्षा में \(-z^2-2z-1\) को (-(z+1)2) समझें।