\(16p^2-24pq+9q^2-r^2\) का गुणनखंडन क्या है?
What is the factorisation of \(16p^2-24pq+9q^2-r^2\)?
Explanation opens after your attempt
A. ((4p-3q-r)(4p-3q+r))
Concept
(16p-2-24pq+9q-2=(4p-3q)2). Subtracting \(r^2\) forms a difference of squares.
Why this answer is correct
The correct answer is A. ((4p-3q-r)(4p-3q+r)). (16p-2-24pq+9q-2=(4p-3q)2). Subtracting \(r^2\) forms a difference of squares.
Exam Tip
(16p-2-24pq+9q-2=(4p-3q)2) है। फिर \(r^2\) घटाने पर वर्गों का अंतर बनता है।
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