What is the expression \(2x^2+\sqrt{7}x-3\)?

Correct answer: Polynomial

In \(2x^2+\sqrt{7}x-3\), the exponents of the variable \(x\) are \(2\), \(1\), and \(0\), all of which are non-negative integers. Its coefficients \(2\), \(\sqrt{7}\), and \(-3\) are real numbers. An irrational coefficient does not stop an expression from being a polynomial, so this is a polynomial. Option B is incorrect because \(\sqrt{7}\) is only an irrational coefficient, not an exponent of the variable. Exam tip: To identify a polynomial, check that every variable exponent is \(0,1,2,\ldots\).