बहुपद (x-8\(x^2+1\)-x-2\(x^8-7\)) की डिग्री क्या है?

What is the degree of (x-8\(x^2+1\)-x-2\(x^8-7\))?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

The simplified form is \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\). Its degree is (8).

Step 2

Why this answer is correct

The correct answer is B. (8). The simplified form is \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\). Its degree is (8).

Step 3

Exam Tip

सरल रूप \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\) है। इसकी डिग्री (8) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

बहुपद (x-8\(x^2+1\)-x-2\(x^8-7\)) की डिग्री क्या है? / What is the degree of (x-8\(x^2+1\)-x-2\(x^8-7\))?

Correct Answer: B. (8). Explanation: सरल रूप \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\) है। इसकी डिग्री (8) है। / The simplified form is \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\). Its degree is (8).

Which concept should I revise for this Mathematics MCQ?

The simplified form is \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\). Its degree is (8).

What exam hint can help solve this Mathematics question?

सरल रूप \(x^{10}+x^8-x^{10}+7x^2=x^8+7x^2\) है। इसकी डिग्री (8) है।