वर्गमूल सर्पिल में \(\sqrt{960}\) का सही अंतराल कौन-सा है?

What is the correct interval for \(\sqrt{960}\) in a square root spiral?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(30<\sqrt{960}<31\)

Step 1

Concept

Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them, so \(\sqrt{960}\) lies between (30) and (31).

Step 2

Why this answer is correct

The correct answer is B. \(30<\sqrt{960}<31\). Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them, so \(\sqrt{960}\) lies between (30) and (31).

Step 3

Exam Tip

क्योंकि \(30^2=900\) और \(31^2=961\) हैं। (960) इनके बीच है, इसलिए \(\sqrt{960}\) (30) और (31) के बीच है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{960}\) का सही अंतराल कौन-सा है? / What is the correct interval for \(\sqrt{960}\) in a square root spiral?

Correct Answer: B. \(30<\sqrt{960}<31\). Explanation: क्योंकि \(30^2=900\) और \(31^2=961\) हैं। (960) इनके बीच है, इसलिए \(\sqrt{960}\) (30) और (31) के बीच है। / Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them, so \(\sqrt{960}\) lies between (30) and (31).

Which concept should I revise for this Mathematics MCQ?

Because \(30^2=900\) and \(31^2=961\). The number (960) lies between them, so \(\sqrt{960}\) lies between (30) and (31).

What exam hint can help solve this Mathematics question?

क्योंकि \(30^2=900\) और \(31^2=961\) हैं। (960) इनके बीच है, इसलिए \(\sqrt{960}\) (30) और (31) के बीच है।