वर्गमूल सर्पिल में \(\sqrt{96}\) का सही अंतराल कौन-सा है?
What is the correct interval for \(\sqrt{96}\) in a square root spiral?
Explanation opens after your attempt
B. \(9<\sqrt{96}<10\)
Concept
Because \(9^2<96<10^2\). Therefore \(\sqrt{96}\) lies between (9) and (10).
Why this answer is correct
The correct answer is B. \(9<\sqrt{96}<10\). Because \(9^2<96<10^2\). Therefore \(\sqrt{96}\) lies between (9) and (10).
Exam Tip
क्योंकि \(9^2<96<10^2\) है। इसलिए \(\sqrt{96}\) (9) और (10) के बीच है।
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