\(\sqrt{108}-\sqrt{48}+\sqrt{12}\) किसके बराबर है?
What is \(\sqrt{108}-\sqrt{48}+\sqrt{12}\) equal to?
Explanation opens after your attempt
A. \(4\sqrt{3}\)
Concept
\(\sqrt{108}=6\sqrt{3}\), \(\sqrt{48}=4\sqrt{3}\), and \(\sqrt{12}=2\sqrt{3}\). Therefore the result is \(4\sqrt{3}\).
Why this answer is correct
The correct answer is A. \(4\sqrt{3}\). \(\sqrt{108}=6\sqrt{3}\), \(\sqrt{48}=4\sqrt{3}\), and \(\sqrt{12}=2\sqrt{3}\). Therefore the result is \(4\sqrt{3}\).
Exam Tip
\(\sqrt{108}=6\sqrt{3}\), \(\sqrt{48}=4\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\) है। इसलिए परिणाम \(4\sqrt{3}\) है।
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