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Riya assumes that \(\sqrt{3}=\frac{a}{b}\), where \(a\) and \(b\) are coprime integers. If the proof shows that both \(a\) and \(b\) are divisible by 3, what conclusion follows?

Answer and explanation

Correct answer: This contradicts the assumption because \(a\) and \(b\) cannot remain coprime.

If both \(a\) and \(b\) are divisible by 3, they have the common factor 3. This contradicts the assumption that they are coprime, so \(\sqrt{3}\) is irrational. Exam tip: state the common factor clearly in a contradiction proof.

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof By ContradictionCoprime IntegersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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