Reema has drawn a square root spiral up to \(\sqrt{10}\). She says that to construct \(\sqrt{11}\), a new line segment of length 1 should be drawn parallel to the previous hypotenuse from its endpoint. Why is her statement incorrect?

Correct answer: The new unit side must be perpendicular to the previous hypotenuse so that a right triangle is formed.

In a square root spiral, the new unit segment is drawn perpendicular to the previous hypotenuse. Thus, \((\sqrt{10})^2+1^2=11\), giving a hypotenuse of \(\sqrt{11}\). A parallel segment does not form the required right triangle. Exam tip: apply Pythagoras at each step.