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Let \(a\) be a rational number and \(b\) be an irrational number. Which of the following expressions will always be irrational?

Answer and explanation

Correct answer: \(a+b\)

The correct expression is \(a+b\). If \(a+b\) were rational, then \(b=(a+b)-a\) would also be rational, a contradiction. However, \(ab=0\) when \(a=0\). Exam tip: test zero when checking an “always” claim.

Related tags

Irrational NumbersRational NumbersNumber SystemsProof By ContradictionAlgebraic PropertiesMathematicsClass 9 Mcq

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