किस स्थिति में \(\sqrt{2}\) के प्रमाण का वास्तविक विरोधाभास बनता है?
In which situation does the real contradiction in the proof of \(\sqrt{2}\) occur?
Explanation opens after your attempt
C. (x) और (y) दोनों सम हों जबकि वे सहभाज्य होंBoth (x) and (y) are even while they are coprime
Concept
The contradiction completes when numerator and denominator both have common factor (2). This opposes the coprime condition.
Why this answer is correct
The correct answer is C. (x) और (y) दोनों सम हों जबकि वे सहभाज्य हों / Both (x) and (y) are even while they are coprime. The contradiction completes when numerator and denominator both have common factor (2). This opposes the coprime condition.
Exam Tip
विरोधाभास तब पूरा होता है जब अंश और हर दोनों में सामान्य गुणनखंड (2) मिल जाए। यह सहभाज्य शर्त के विरुद्ध है।
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