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In which situation does the real contradiction in the proof of (\sqrt{2}) occur?किस स्थिति में (\sqrt{2}) के प्रमाण का वास्तविक विरोधाभास बनता है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Both (x) and (y) are even while they are coprime(x) और (y) दोनों सम हों जबकि वे सहभाज्य हों
The contradiction completes when numerator and denominator both have common factor (2). This opposes the coprime condition.विरोधाभास तब पूरा होता है जब अंश और हर दोनों में सामान्य गुणनखंड (2) मिल जाए। यह सहभाज्य शर्त के विरुद्ध है।
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