\(\sqrt{3}\) के प्रमाण में यदि (p) (3) से विभाज्य न हो, तो \(p^2=3q^2\) से टकराव क्यों बनता है?
In the proof of \(\sqrt{3}\), if (p) is not divisible by (3), why does \(p^2=3q^2\) create conflict?
Explanation opens after your attempt
A. तब \(p^2\) (3) से विभाज्य नहीं होगा, पर समीकरण उसे विभाज्य दिखाता हैThen \(p^2\) would not be divisible by (3), but the equation shows it is divisible
Concept
Prime factor (3) appears in \(p^2\) only if it appears in (p). The equation forces this divisibility.
Why this answer is correct
The correct answer is A. तब \(p^2\) (3) से विभाज्य नहीं होगा, पर समीकरण उसे विभाज्य दिखाता है / Then \(p^2\) would not be divisible by (3), but the equation shows it is divisible. Prime factor (3) appears in \(p^2\) only if it appears in (p). The equation forces this divisibility.
Exam Tip
अभाज्य (3) का गुणनखंड \(p^2\) में तभी होगा जब (p) में हो। समीकरण इस विभाज्यता को अनिवार्य करता है।
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