\(\sqrt{2}\) के प्रमाण में (a) और (b) को सहभाज्य मानना केवल औपचारिकता नहीं है, क्योंकि इससे क्या सिद्ध होता है?

In the proof of \(\sqrt{2}\), assuming (a) and (b) coprime is not just formality because what does it help prove?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. दोनों सम निकलने पर वास्तविक विरोधाभासA real contradiction when both become even

Step 1

Concept

Without the coprime condition, both even would not create a contradiction. Lowest form is the backbone of the proof.

Step 2

Why this answer is correct

The correct answer is A. दोनों सम निकलने पर वास्तविक विरोधाभास / A real contradiction when both become even. Without the coprime condition, both even would not create a contradiction. Lowest form is the backbone of the proof.

Step 3

Exam Tip

यदि सहभाज्य शर्त न हो, तो दोनों सम मिलना विरोधाभास नहीं बनेगा। सरलतम रूप प्रमाण की रीढ़ है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{2}\) के प्रमाण में (a) और (b) को सहभाज्य मानना केवल औपचारिकता नहीं है, क्योंकि इससे क्या सिद्ध होता है? / In the proof of \(\sqrt{2}\), assuming (a) and (b) coprime is not just formality because what does it help prove?

Correct Answer: A. दोनों सम निकलने पर वास्तविक विरोधाभास / A real contradiction when both become even. Explanation: यदि सहभाज्य शर्त न हो, तो दोनों सम मिलना विरोधाभास नहीं बनेगा। सरलतम रूप प्रमाण की रीढ़ है। / Without the coprime condition, both even would not create a contradiction. Lowest form is the backbone of the proof.

Which concept should I revise for this Mathematics MCQ?

Without the coprime condition, both even would not create a contradiction. Lowest form is the backbone of the proof.

What exam hint can help solve this Mathematics question?

यदि सहभाज्य शर्त न हो, तो दोनों सम मिलना विरोधाभास नहीं बनेगा। सरलतम रूप प्रमाण की रीढ़ है।