0 reads0 ratings0 helpful
In constructing a square root spiral, a student uses a hypotenuse of \(\sqrt{6}\) and draws a perpendicular side of 1 unit. Which number will the new hypotenuse represent?वर्गमूल सर्पिल बनाते समय एक विद्यार्थी
display?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\sqrt{7}\)\(\sqrt{7}\)
By Pythagoras, the square of the new hypotenuse is \((\sqrt{6})^2+1^2=6+1=7\). Hence it represents \(\sqrt{7}\). \(\sqrt{6}\) is the previous hypotenuse. Exam tip: square the old length first.समकोण त्रिभुज में नई कर्ण का वर्ग \((\sqrt{6})^2+1^2=6+1=7\) होता है। इसलिए नई कर्ण \(\sqrt{7}\) है। \(\sqrt{6}\) पुरानी कर्ण है। परीक्षा में कर्ण का वर्ग पहले निकालें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
