वर्गमूल सर्पिल में \(\sqrt{255}\) के बाद बनने वाला कर्ण किस विशेष मान पर स्थित होगा?
In a square root spiral, the hypotenuse formed after \(\sqrt{255}\) will be located at which special value?
Explanation opens after your attempt
B. \(\sqrt{256}=16\)
Concept
The next hypotenuse is \(\sqrt{256}\). Since \(256=16^2\), it is located exactly at (16).
Why this answer is correct
The correct answer is B. \(\sqrt{256}=16\). The next hypotenuse is \(\sqrt{256}\). Since \(256=16^2\), it is located exactly at (16).
Exam Tip
अगला कर्ण \(\sqrt{256}\) है। \(256=16^2\), इसलिए यह ठीक (16) पर स्थित है।
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