वर्गमूल सर्पिल में \(\sqrt{255}\) के बाद बनने वाला कर्ण किस विशेष मान पर स्थित होगा?

In a square root spiral, the hypotenuse formed after \(\sqrt{255}\) will be located at which special value?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{256}=16\)

Step 1

Concept

The next hypotenuse is \(\sqrt{256}\). Since \(256=16^2\), it is located exactly at (16).

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{256}=16\). The next hypotenuse is \(\sqrt{256}\). Since \(256=16^2\), it is located exactly at (16).

Step 3

Exam Tip

अगला कर्ण \(\sqrt{256}\) है। \(256=16^2\), इसलिए यह ठीक (16) पर स्थित है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{255}\) के बाद बनने वाला कर्ण किस विशेष मान पर स्थित होगा? / In a square root spiral, the hypotenuse formed after \(\sqrt{255}\) will be located at which special value?

Correct Answer: B. \(\sqrt{256}=16\). Explanation: अगला कर्ण \(\sqrt{256}\) है। \(256=16^2\), इसलिए यह ठीक (16) पर स्थित है। / The next hypotenuse is \(\sqrt{256}\). Since \(256=16^2\), it is located exactly at (16).

Which concept should I revise for this Mathematics MCQ?

The next hypotenuse is \(\sqrt{256}\). Since \(256=16^2\), it is located exactly at (16).

What exam hint can help solve this Mathematics question?

अगला कर्ण \(\sqrt{256}\) है। \(256=16^2\), इसलिए यह ठीक (16) पर स्थित है।