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If \(x\) is an irrational number and \(r\) is a non-zero rational number, what type of number must \(rx\) be?

Answer and explanation

Correct answer: Irrational

Assume \(rx\) is rational. Since \(r\ne0\) is rational, \(x=(rx)/r\) would also be rational, giving a contradiction. Hence \(rx\) is irrational. In exams, always check that the rational multiplier is non-zero.

Related tags

Irrational NumbersRational NumbersNumber SystemsProof By ContradictionMultiplication PropertyMathematicsClass 9 Mcq

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