यदि \(x=-15\) है, तो \(\sqrt{x^2}-x\) का मान क्या होगा?
If \(x=-15\), what is the value of \(\sqrt{x^2}-x\)?
Explanation opens after your attempt
C. 30
Simple Explanation
यहाँ \(\sqrt{x^2}=|x|\) होता है, न कि हमेशा \(x\)। क्योंकि \(x=-15\) है, इसलिए \(\sqrt{x^2}=|-15|=15\)। अतः \(\sqrt{x^2}-x=15-(-15)=30\)। विकल्प \(0\) तब मिलता यदि गलती से \(\sqrt{x^2}=x\) मान लिया जाए। परीक्षा टिप: वर्गमूल का मुख्य मान सदैव ऋणेतर होता है, इसलिए \(\sqrt{x^2}=|x|\) लिखें। / Use \(\sqrt{x^2}=|x|\), not simply \(x\) in every case. Since \(x=-15\), \(\sqrt{x^2}=|-15|=15\). Therefore, \(\sqrt{x^2}-x=15-(-15)=30\). The option \(0\) results from the incorrect assumption that \(\sqrt{x^2}=x\) for a negative value of \(x\). Exam tip: the principal square root is always non-negative, so write \(\sqrt{x^2}=|x|\).
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