वर्गमूल सर्पिल में यदि (k)वाँ कर्ण \(\sqrt{k}\) माना जाए, तो \(\sqrt{25}\) कौन-सा कर्ण होगा और उसका मान क्या होगा?
If the (k)-th hypotenuse in a square root spiral is considered as \(\sqrt{k}\), which hypotenuse is \(\sqrt{25}\), and what is its value?
Explanation opens after your attempt
B. (25)वाँ, (5)(25)-th, (5)
Concept
If the (k)-th hypotenuse is \(\sqrt{k}\), then \(\sqrt{25}\) is the (25)-th hypotenuse. Also, \(\sqrt{25}=5\).
Why this answer is correct
The correct answer is B. (25)वाँ, (5) / (25)-th, (5). If the (k)-th hypotenuse is \(\sqrt{k}\), then \(\sqrt{25}\) is the (25)-th hypotenuse. Also, \(\sqrt{25}=5\).
Exam Tip
यदि (k)वाँ कर्ण \(\sqrt{k}\) है, तो \(\sqrt{25}\) (25)वाँ कर्ण है। \(\sqrt{25}=5\) होता है।
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