यदि \(r=\sqrt{7}+\sqrt{2}\) और \(s=\sqrt{7}-\sqrt{2}\) हैं तो \(r^2-s^2\) का मान क्या है?
If \(r=\sqrt{7}+\sqrt{2}\) and \(s=\sqrt{7}-\sqrt{2}\), what is the value of \(r^2-s^2\)?
Explanation opens after your attempt
Correct Answer
A. \(4\sqrt{14}\)
Concept
(r-2-s-2=(r-s)(r+s)) where \(r-s=2\sqrt{2}\) and \(r+s=2\sqrt{7}\). So the value is \(4\sqrt{14}\).
Why this answer is correct
The correct answer is A. \(4\sqrt{14}\). (r-2-s-2=(r-s)(r+s)) where \(r-s=2\sqrt{2}\) and \(r+s=2\sqrt{7}\). So the value is \(4\sqrt{14}\).
Exam Tip
(r-2-s-2=(r-s)(r+s)) है जहाँ \(r-s=2\sqrt{2}\) और \(r+s=2\sqrt{7}\) है। इसलिए मान \(4\sqrt{14}\) है।
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