यदि (p(x)=x-7\(x^2-8\)-x-9+8x-7+43), तो (p(x)) की डिग्री क्या है?
If (p(x)=x-7\(x^2-8\)-x-9+8x-7+43), what is the degree of (p(x))?
Explanation opens after your attempt
C. (0)
Concept
(x-7\(x^2-8\)=x-9-8x-7). All variable terms cancel and (43) remains, whose degree is (0).
Why this answer is correct
The correct answer is C. (0). (x-7\(x^2-8\)=x-9-8x-7). All variable terms cancel and (43) remains, whose degree is (0).
Exam Tip
(x-7\(x^2-8\)=x-9-8x-7) है। सभी चर पद कट जाते हैं और (43) बचता है जिसकी डिग्री (0) है।
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