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If (p(x)=x^5(x^3+x)-x^8-x^6+37), what is the degree of (p(x))?यदि (p(x)=x^5(x^3+x)-x^8-x^6+37), तो (p(x)) की डिग्री क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 00
First simplify the expression: \(x^5(x^3+x)=x^8+x^6\). Therefore, \(p(x)=x^8+x^6-x^8-x^6+37=37\). Since 37 is a non-zero constant polynomial, its degree is \(0\). The values \(8\) and \(6\) are powers of terms before simplification, but those terms cancel. Exam tip: always simplify a polynomial completely before finding its degree.पहले व्यंजक को सरल करें: \(x^5(x^3+x)=x^8+x^6\)। अतः \(p(x)=x^8+x^6-x^8-x^6+37=37\)। 37 एक शून्येतर अचर बहुपद है, इसलिए इसकी डिग्री \(0\) होती है। \(8\) या \(6\) सरल करने से पहले के पदों की घात हैं; वे आपस में कट जाते हैं। परीक्षा टिप: डिग्री ज्ञात करने से पहले बहुपद को हमेशा पूर्णतः सरल करें।
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