यदि (p(x)=kx+11) और (p(6)=p(-2)), तो (p(x)) रेखीय कब रहेगा?
If (p(x)=kx+11) and (p(6)=p(-2)), when will (p(x)) remain linear?
Explanation opens after your attempt
C. कभी नहींNever
Concept
From (p(6)=p(-2)), (6k+11=-2k+11), so (k=0). At (k=0), the polynomial is not linear.
Why this answer is correct
The correct answer is C. कभी नहीं / Never. From (p(6)=p(-2)), (6k+11=-2k+11), so (k=0). At (k=0), the polynomial is not linear.
Exam Tip
(p(6)=p(-2)) से (6k+11=-2k+11) और (k=0) मिलता है। (k=0) पर बहुपद रेखीय नहीं रहता।
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