If (p(x)=ax+18) and (p(-3)=0), what is the value of (a)?
Answer and explanation
Correct answer: \(6\)
Given \(p(x)=ax+18\), substituting \(x=-3\) gives \(p(-3)=-3a+18\). Since \(p(-3)=0\), we get \(-3a+18=0\), so \(a=6\). If \(a=-6\), then \(p(-3)=36\), not zero. Exam tip: Substitute the given value of \(x\) carefully before solving for the unknown coefficient.
Frequently asked questions
What is the correct answer to this question?
\(6\)
Why is this the correct answer?
Given \(p(x)=ax+18\), substituting \(x=-3\) gives \(p(-3)=-3a+18\). Since \(p(-3)=0\), we get \(-3a+18=0\), so \(a=6\). If \(a=-6\), then \(p(-3)=36\), not zero. Exam tip: Substitute the given value of \(x\) carefully before solving for the unknown coefficient.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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