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If (p(x)=9x-1), what is the value of (p(1)+p(0))?

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Answer and explanation

Correct answer: \(7\)

Given \(p(x)=9x-1\), we get \(p(1)=9(1)-1=8\) and \(p(0)=9(0)-1=-1\). Therefore, \(p(1)+p(0)=8+(-1)=7\). Note that \(8\) is only the value of \(p(1)\), not their sum. Exam tip: After substituting a value in a polynomial, check the signs of all terms carefully.

Related tags

PolynomialsLinear PolynomialsEvaluating PolynomialsClass 9 MathematicsSubstitution

Frequently asked questions

What is the correct answer to this question?

\(7\)

Why is this the correct answer?

Given \(p(x)=9x-1\), we get \(p(1)=9(1)-1=8\) and \(p(0)=9(0)-1=-1\). Therefore, \(p(1)+p(0)=8+(-1)=7\). Note that \(8\) is only the value of \(p(1)\), not their sum. Exam tip: After substituting a value in a polynomial, check the signs of all terms carefully.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.

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