If (p(x)=9x-1), what is the value of (p(1)+p(0))?
Answer and explanation
Correct answer: \(7\)
Given \(p(x)=9x-1\), we get \(p(1)=9(1)-1=8\) and \(p(0)=9(0)-1=-1\). Therefore, \(p(1)+p(0)=8+(-1)=7\). Note that \(8\) is only the value of \(p(1)\), not their sum. Exam tip: After substituting a value in a polynomial, check the signs of all terms carefully.
Frequently asked questions
What is the correct answer to this question?
\(7\)
Why is this the correct answer?
Given \(p(x)=9x-1\), we get \(p(1)=9(1)-1=8\) and \(p(0)=9(0)-1=-1\). Therefore, \(p(1)+p(0)=8+(-1)=7\). Note that \(8\) is only the value of \(p(1)\), not their sum. Exam tip: After substituting a value in a polynomial, check the signs of all terms carefully.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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