यदि (p(x)=6x+a) और (q(x)=3x-10), तो (p(x)+q(x)) का शून्यक (2) होने पर (a) क्या है?
If (p(x)=6x+a) and (q(x)=3x-10), what is (a) if the zero of (p(x)+q(x)) is (2)?
Explanation opens after your attempt
A. (-8)
Concept
(p(x)+q(x)=9x+a-10). Substituting (x=2) gives (18+a-10=0), so (a=-8).
Why this answer is correct
The correct answer is A. (-8). (p(x)+q(x)=9x+a-10). Substituting (x=2) gives (18+a-10=0), so (a=-8).
Exam Tip
(p(x)+q(x)=9x+a-10) है। (x=2) रखने पर (18+a-10=0) से (a=-8) मिलता है।
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