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If (p(x)=6x+1) and (p(t)=31), what is the value of (t)?

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Answer and explanation

Correct answer: 5

Given p(x)=6x+1, substituting t for x gives p(t)=6t+1. Since p(t)=31, we get 6t+1=31, so 6t=30 and t=5. For example, t=4 gives p(4)=25, not 31. Exam tip: In p(t), replace x directly with t before solving the equation.

Related tags

PolynomialsLinear PolynomialsFunction EvaluationAlgebraic SubstitutionClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

5

Why is this the correct answer?

Given p(x)=6x+1, substituting t for x gives p(t)=6t+1. Since p(t)=31, we get 6t+1=31, so 6t=30 and t=5. For example, t=4 gives p(4)=25, not 31. Exam tip: In p(t), replace x directly with t before solving the equation.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.

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