If (p(x)=6x+1) and (p(t)=31), what is the value of (t)?
Answer and explanation
Correct answer: 5
Given p(x)=6x+1, substituting t for x gives p(t)=6t+1. Since p(t)=31, we get 6t+1=31, so 6t=30 and t=5. For example, t=4 gives p(4)=25, not 31. Exam tip: In p(t), replace x directly with t before solving the equation.
Frequently asked questions
What is the correct answer to this question?
5
Why is this the correct answer?
Given p(x)=6x+1, substituting t for x gives p(t)=6t+1. Since p(t)=31, we get 6t+1=31, so 6t=30 and t=5. For example, t=4 gives p(4)=25, not 31. Exam tip: In p(t), replace x directly with t before solving the equation.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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