यदि \(OP=\sqrt{x}\) और अगला कर्ण \(\sqrt{57}\) है, तो (x) का मान क्या होगा?

If \(OP=\sqrt{x}\) and the next hypotenuse is \(\sqrt{57}\), what is the value of (x)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (56)

Step 1

Concept

The next hypotenuse is \(\sqrt{x+1}\), so (x+1=57). This gives (x=56).

Step 2

Why this answer is correct

The correct answer is B. (56). The next hypotenuse is \(\sqrt{x+1}\), so (x+1=57). This gives (x=56).

Step 3

Exam Tip

अगला कर्ण \(\sqrt{x+1}\) होता है, इसलिए (x+1=57)। इससे (x=56) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(OP=\sqrt{x}\) और अगला कर्ण \(\sqrt{57}\) है, तो (x) का मान क्या होगा? / If \(OP=\sqrt{x}\) and the next hypotenuse is \(\sqrt{57}\), what is the value of (x)?

Correct Answer: B. (56). Explanation: अगला कर्ण \(\sqrt{x+1}\) होता है, इसलिए (x+1=57)। इससे (x=56) मिलता है। / The next hypotenuse is \(\sqrt{x+1}\), so (x+1=57). This gives (x=56).

Which concept should I revise for this Mathematics MCQ?

The next hypotenuse is \(\sqrt{x+1}\), so (x+1=57). This gives (x=56).

What exam hint can help solve this Mathematics question?

अगला कर्ण \(\sqrt{x+1}\) होता है, इसलिए (x+1=57)। इससे (x=56) मिलता है।