वर्गमूल सर्पिल में \(\sqrt{75}\) बनाने के बाद नया कर्ण \(\sqrt{76}\) बने तो वह किस अंतराल में होगा?
If after constructing \(\sqrt{75}\), the new hypotenuse \(\sqrt{76}\) is formed in a square root spiral, in which interval will it lie?
Explanation opens after your attempt
B. (8) और (9) के बीचBetween (8) and (9)
Concept
Because \(8^2<76<9^2\). Therefore \(\sqrt{76}\) lies between (8) and (9).
Why this answer is correct
The correct answer is B. (8) और (9) के बीच / Between (8) and (9). Because \(8^2<76<9^2\). Therefore \(\sqrt{76}\) lies between (8) and (9).
Exam Tip
क्योंकि \(8^2<76<9^2\) है। इसलिए \(\sqrt{76}\) (8) और (9) के बीच होगा।
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