वर्गमूल सर्पिल में \(\sqrt{75}\) बनाने के बाद नया कर्ण \(\sqrt{76}\) बने तो वह किस अंतराल में होगा?

If after constructing \(\sqrt{75}\), the new hypotenuse \(\sqrt{76}\) is formed in a square root spiral, in which interval will it lie?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (8) और (9) के बीचBetween (8) and (9)

Step 1

Concept

Because \(8^2<76<9^2\). Therefore \(\sqrt{76}\) lies between (8) and (9).

Step 2

Why this answer is correct

The correct answer is B. (8) और (9) के बीच / Between (8) and (9). Because \(8^2<76<9^2\). Therefore \(\sqrt{76}\) lies between (8) and (9).

Step 3

Exam Tip

क्योंकि \(8^2<76<9^2\) है। इसलिए \(\sqrt{76}\) (8) और (9) के बीच होगा।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{75}\) बनाने के बाद नया कर्ण \(\sqrt{76}\) बने तो वह किस अंतराल में होगा? / If after constructing \(\sqrt{75}\), the new hypotenuse \(\sqrt{76}\) is formed in a square root spiral, in which interval will it lie?

Correct Answer: B. (8) और (9) के बीच / Between (8) and (9). Explanation: क्योंकि \(8^2<76<9^2\) है। इसलिए \(\sqrt{76}\) (8) और (9) के बीच होगा। / Because \(8^2<76<9^2\). Therefore \(\sqrt{76}\) lies between (8) and (9).

Which concept should I revise for this Mathematics MCQ?

Because \(8^2<76<9^2\). Therefore \(\sqrt{76}\) lies between (8) and (9).

What exam hint can help solve this Mathematics question?

क्योंकि \(8^2<76<9^2\) है। इसलिए \(\sqrt{76}\) (8) और (9) के बीच होगा।