यदि \(a=\sqrt{3}+\sqrt{2}\) है तो \(a^2+\frac{1}{a^2}\) का मान क्या है?
If \(a=\sqrt{3}+\sqrt{2}\), what is the value of \(a^2+\frac{1}{a^2}\)?
Explanation opens after your attempt
Correct Answer
B. (98)
Concept
\(a^2=5+2\sqrt{6}\) and \( \frac{1}{a^2}=5-2\sqrt{6} \). The sum should be (10).
Why this answer is correct
The correct answer is B. (98). \(a^2=5+2\sqrt{6}\) and \( \frac{1}{a^2}=5-2\sqrt{6} \). The sum should be (10).
Exam Tip
\(a^2=5+2\sqrt{6}\) और \( \frac{1}{a^2}=5-2\sqrt{6} \)। योग (10) होना चाहिए।
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