यदि \(a_n=\frac{n}{n+2}\) है तो पहला पद जो \(\frac{4}{5}\) से बड़ा है कौन सा होगा?

If \(a_n=\frac{n}{n+2}\), which is the first term greater than \(\frac{4}{5}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (9)वाँ(9)th

Step 1

Concept

From \(\frac{n}{n+2}>\frac{4}{5}\), we get (n>8). The first integer is (n=9).

Step 2

Why this answer is correct

The correct answer is A. (9)वाँ / (9)th. From \(\frac{n}{n+2}>\frac{4}{5}\), we get (n>8). The first integer is (n=9).

Step 3

Exam Tip

\(\frac{n}{n+2}>\frac{4}{5}\) से (n>8) मिलता है। पहला पूर्णांक (n=9) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_n=\frac{n}{n+2}\) है तो पहला पद जो \(\frac{4}{5}\) से बड़ा है कौन सा होगा? / If \(a_n=\frac{n}{n+2}\), which is the first term greater than \(\frac{4}{5}\)?

Correct Answer: A. (9)वाँ / (9)th. Explanation: \(\frac{n}{n+2}>\frac{4}{5}\) से (n>8) मिलता है। पहला पूर्णांक (n=9) है। / From \(\frac{n}{n+2}>\frac{4}{5}\), we get (n>8). The first integer is (n=9).

Which concept should I revise for this Mathematics MCQ?

From \(\frac{n}{n+2}>\frac{4}{5}\), we get (n>8). The first integer is (n=9).

What exam hint can help solve this Mathematics question?

\(\frac{n}{n+2}>\frac{4}{5}\) से (n>8) मिलता है। पहला पूर्णांक (n=9) है।