यदि \(a_n=\frac{n^2-1}{n+1}\) है तो \(a_{15}\) का मान क्या होगा?

If \(a_n=\frac{n^2-1}{n+1}\), what will be the value of \(a_{15}\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (14)

Step 1

Concept

\(\frac{n^2-1}{n+1}=n-1\). Therefore \(a_{15}=14\).

Step 2

Why this answer is correct

The correct answer is C. (14). \(\frac{n^2-1}{n+1}=n-1\). Therefore \(a_{15}=14\).

Step 3

Exam Tip

\(\frac{n^2-1}{n+1}=n-1\) होता है। इसलिए \(a_{15}=14\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_n=\frac{n^2-1}{n+1}\) है तो \(a_{15}\) का मान क्या होगा? / If \(a_n=\frac{n^2-1}{n+1}\), what will be the value of \(a_{15}\)?

Correct Answer: C. (14). Explanation: \(\frac{n^2-1}{n+1}=n-1\) होता है। इसलिए \(a_{15}=14\) है। / \(\frac{n^2-1}{n+1}=n-1\). Therefore \(a_{15}=14\).

Which concept should I revise for this Mathematics MCQ?

\(\frac{n^2-1}{n+1}=n-1\). Therefore \(a_{15}=14\).

What exam hint can help solve this Mathematics question?

\(\frac{n^2-1}{n+1}=n-1\) होता है। इसलिए \(a_{15}=14\) है।