यदि \(a_n=125\left(\frac{1}{5}\right)^{n-1}\) है, तो \(a_2+a_4\) कितना होगा?
If \(a_n=125\left(\frac{1}{5}\right)^{n-1}\), what is \(a_2+a_4\)?
Explanation opens after your attempt
A. (26)
Concept
\(a_2=25\) and \(a_4=1\), so the sum is (26). With a fractional ratio, terms decrease quickly.
Why this answer is correct
The correct answer is A. (26). \(a_2=25\) and \(a_4=1\), so the sum is (26). With a fractional ratio, terms decrease quickly.
Exam Tip
\(a_2=25\) और \(a_4=1\), इसलिए योग (26) है। भिन्न अनुपात में हर पद तेजी से घटता है।
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