यदि \(a_1=90\) और (a_{n+1}=a_n-\(n^2+n\)) है तो \(a_4\) क्या होगा?

If \(a_1=90\) and (a_{n+1}=a_n-\(n^2+n\)), what is \(a_4\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (70)

Step 1

Concept

The terms are (90,88,82,70), so \(a_4=70\). Exam tip: subtract (2,6,12) in order.

Step 2

Why this answer is correct

The correct answer is B. (70). The terms are (90,88,82,70), so \(a_4=70\). Exam tip: subtract (2,6,12) in order.

Step 3

Exam Tip

पद (90,88,82,70) हैं इसलिए \(a_4=70\) है। \(n^2+n\) के मान (2,6,12) क्रम से घटाएँ।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=90\) और (a_{n+1}=a_n-\(n^2+n\)) है तो \(a_4\) क्या होगा? / If \(a_1=90\) and (a_{n+1}=a_n-\(n^2+n\)), what is \(a_4\)?

Correct Answer: B. (70). Explanation: पद (90,88,82,70) हैं इसलिए \(a_4=70\) है। \(n^2+n\) के मान (2,6,12) क्रम से घटाएँ। / The terms are (90,88,82,70), so \(a_4=70\). Exam tip: subtract (2,6,12) in order.

Which concept should I revise for this Mathematics MCQ?

The terms are (90,88,82,70), so \(a_4=70\). Exam tip: subtract (2,6,12) in order.

What exam hint can help solve this Mathematics question?

पद (90,88,82,70) हैं इसलिए \(a_4=70\) है। \(n^2+n\) के मान (2,6,12) क्रम से घटाएँ।