यदि \(a_1=80\) और (a_{n+1}=a_n-\frac{n(n+1)}{2}-1) है तो \(a_4\) क्या होगा?

If \(a_1=80\) and (a_{n+1}=a_n-\frac{n(n+1)}{2}-1), what is \(a_4\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (69)

Step 1

Concept

The terms are (80,78,74,67), so \(a_4=67\). Exam tip: the subtractions are (2,4,7) in order.

Step 2

Why this answer is correct

The correct answer is A. (69). The terms are (80,78,74,67), so \(a_4=67\). Exam tip: the subtractions are (2,4,7) in order.

Step 3

Exam Tip

पद (80,78,74,67) नहीं बल्कि \(a_4=67\) है। घटाव (2,4,7) क्रम से होता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=80\) और (a_{n+1}=a_n-\frac{n(n+1)}{2}-1) है तो \(a_4\) क्या होगा? / If \(a_1=80\) and (a_{n+1}=a_n-\frac{n(n+1)}{2}-1), what is \(a_4\)?

Correct Answer: A. (69). Explanation: पद (80,78,74,67) नहीं बल्कि \(a_4=67\) है। घटाव (2,4,7) क्रम से होता है। / The terms are (80,78,74,67), so \(a_4=67\). Exam tip: the subtractions are (2,4,7) in order.

Which concept should I revise for this Mathematics MCQ?

The terms are (80,78,74,67), so \(a_4=67\). Exam tip: the subtractions are (2,4,7) in order.

What exam hint can help solve this Mathematics question?

पद (80,78,74,67) नहीं बल्कि \(a_4=67\) है। घटाव (2,4,7) क्रम से होता है।