यदि (9,x,81) गुणोत्तर श्रेढ़ी के लगातार धनात्मक पद हैं, तो (x) क्या होगा?
If (9,x,81) are consecutive positive terms of a geometric progression, what is (x)?
Explanation opens after your attempt
C. (27)
Concept
\(x^2=9\cdot81=729\), so positive (x=27). The middle term is the geometric mean.
Why this answer is correct
The correct answer is C. (27). \(x^2=9\cdot81=729\), so positive (x=27). The middle term is the geometric mean.
Exam Tip
\(x^2=9\cdot81=729\), इसलिए धनात्मक (x=27)। मध्य पद ज्यामितीय माध्य होता है।
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