किस (x) के लिए (16,x,81) धनात्मक गुणोत्तर श्रेढ़ी के लगातार पद होंगे?

For which (x) will (16,x,81) be consecutive terms of a positive geometric progression?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. (36)

Step 1

Concept

\(x^2=16\cdot81=1296\), so positive (x=36). The middle term is the geometric mean.

Step 2

Why this answer is correct

The correct answer is C. (36). \(x^2=16\cdot81=1296\), so positive (x=36). The middle term is the geometric mean.

Step 3

Exam Tip

\(x^2=16\cdot81=1296\), इसलिए धनात्मक (x=36)। मध्य पद ज्यामितीय माध्य होता है।

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Mathematics Answer, Explanation and Revision Hints

किस (x) के लिए (16,x,81) धनात्मक गुणोत्तर श्रेढ़ी के लगातार पद होंगे? / For which (x) will (16,x,81) be consecutive terms of a positive geometric progression?

Correct Answer: C. (36). Explanation: \(x^2=16\cdot81=1296\), इसलिए धनात्मक (x=36)। मध्य पद ज्यामितीय माध्य होता है। / \(x^2=16\cdot81=1296\), so positive (x=36). The middle term is the geometric mean.

Which concept should I revise for this Mathematics MCQ?

\(x^2=16\cdot81=1296\), so positive (x=36). The middle term is the geometric mean.

What exam hint can help solve this Mathematics question?

\(x^2=16\cdot81=1296\), इसलिए धनात्मक (x=36)। मध्य पद ज्यामितीय माध्य होता है।