\(9x^2+12xy+4y^2-16\) का सही गुणनखंडन चुनिए।

Choose the correct factorisation of \(9x^2+12xy+4y^2-16\).

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((3x+2y-4)(3x+2y+4))

Step 1

Concept

First (9x-2+12xy+4y-2=(3x+2y)2). Then subtract \(16=4^2\) and use difference of squares.

Step 2

Why this answer is correct

The correct answer is A. ((3x+2y-4)(3x+2y+4)). First (9x-2+12xy+4y-2=(3x+2y)2). Then subtract \(16=4^2\) and use difference of squares.

Step 3

Exam Tip

पहले (9x-2+12xy+4y-2=(3x+2y)2) है। फिर \(16=4^2\) घटाकर अंतर के वर्ग लगाएं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(9x^2+12xy+4y^2-16\) का सही गुणनखंडन चुनिए। / Choose the correct factorisation of \(9x^2+12xy+4y^2-16\).

Correct Answer: A. ((3x+2y-4)(3x+2y+4)). Explanation: पहले (9x-2+12xy+4y-2=(3x+2y)2) है। फिर \(16=4^2\) घटाकर अंतर के वर्ग लगाएं। / First (9x-2+12xy+4y-2=(3x+2y)2). Then subtract \(16=4^2\) and use difference of squares.

Which concept should I revise for this Mathematics MCQ?

First (9x-2+12xy+4y-2=(3x+2y)2). Then subtract \(16=4^2\) and use difference of squares.

What exam hint can help solve this Mathematics question?

पहले (9x-2+12xy+4y-2=(3x+2y)2) है। फिर \(16=4^2\) घटाकर अंतर के वर्ग लगाएं।